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|
open OUnit2
let u = UTF8.from_utf8string
let _msg ~(expected:Expression.t) ~(result:Expression.t) =
Printf.sprintf "Expected %s but got %s"
(UTF8.raw_encode @@ Expression.show @@ Expression.load_expr expected)
(UTF8.raw_encode @@ Expression.show @@ Expression.load_expr result)
let load_expr str =
Expression.Formula (
Expression.Expression(
ExpressionParser.value ExpressionLexer.read
@@ Lexing.from_string str )
)
let test_num ctx = begin
let expected = Expression.Formula (
Expression.Expression (
ScTypes.Expr.value (ScTypes.Type.number (
DataType.Num.of_int 1
)
))) in
let result = load_expr "=1" in
assert_equal
~msg:(_msg ~expected ~result)
expected
result
end
let test_call ctx = begin
let expected = Expression.Formula (
Expression.Expression (
ScTypes.Expr.call0 (u"sum"))) in
let result = load_expr "=sum()" in
assert_equal
~msg:(_msg ~expected ~result)
expected
result
end
let test_call2 ctx = begin
(* The expression "foo2(" has to be parsed as a function call, and not as a
reference to cell "FOO2", followed by another expression. *)
let expected = Expression.Formula (
Expression.Expression (
ScTypes.Expr.call1
(u"foo2") (ScTypes.Expr.value (ScTypes.Type.number (
DataType.Num.of_int 4)
)))) in
let result = load_expr "=foo2(4)" in
assert_equal
~msg:(_msg ~expected ~result)
expected
result
end
let test_ref ctx = begin
let expected = Expression.Formula (
Expression.Expression (
ScTypes.Expr.ref(
ScTypes.Refs.cell ((1, 3), (false, false))))) in
let result = load_expr "=A3" in
assert_equal
~msg:(_msg ~expected ~result)
expected
result
end
let tests = "expression_parser_test">::: [
"test_num" >:: test_num;
"test_call" >:: test_call;
"test_call2" >:: test_call2;
"test_ref" >:: test_ref;
]
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